#include<iostream>
using namespace std;
int main() {
  int i,j,k,g,n,h,ans,tot,tt=0,f[32],d[32],t[32],now[32],tnow[32],times[32];
  while (scanf("%d",&n),n) {
  if (tt++)  printf("\n");
  scanf("%d",&h);
  h*=12;
  for (i=0;i<n;++i)  {
               scanf("%d",&f[i]);
               now[i]=f[i];
              }
              for (i=0;i<n;++i)
                     scanf("%d",&d[i]);
              for (i=0;i<n-1;++i)
                     scanf("%d",&t[i]);
              memset(times,0,sizeof(times));
              for (ans=i=0;i<n&&h>0;++i)
              {
                     for (j=0;j<i;++j)
                            now[j]=f[j];
                     memset(tnow,0,sizeof(tnow));
                     for (tot=k=0;k<h;++k)
                     {
                            for (g=0,j=1;j<=i;++j)
                                   if (now[j]>now[g])
                                          g=j;
                            tot+=now[g];
                            now[g]-=d[g];
                            if (now[g]<0)
                                   now[g]=0;
                            ++tnow[g];
                     }
                     if (tot>ans)
                     {
                            ans=tot;
                            for (j=0;j<n;++j)
                                   times[j]=tnow[j];
                     }
                     else if (tot==ans)
                     {
                            for (j=0;j<n;++j)
                                   if (tnow[j]!=times[j])
                                          break;
                            if (j<n&&tnow[j]>times[j])
                                   for (g=j;g<n;++g)
                                          times[g]=tnow[g];
                     }
                     h-=t[i];
              }
              for (i=0;i<n-1;++i)
                     printf("%d, ",times[i]*5);
              printf("%d\nNumber of fish expected: %d\n",times[n-1]*5,ans);
       }
       return 0;
}